W - Required dehumidification amount (kg/h) ρ———— Density of air (kg/m3) 1.2 V -- site volume X2-- air humidity before dehumidification X1-- air humidity after dehumidification 1000-- g converted to kg 1.2-- Factor of safety (loss) W=V ×ρ× (X2-X1) ÷ 1000 × 1.2=(kg/h) Bring into known conditions Example 1: Space volume 20000m2 × 2m high, with an ambient temperature of 20 ℃ and a relative humidity of 90%. How much water needs to be pumped out to reduce it to 70%? Example 2: Space volume 50000m2 × 2m high, with an ambient temperature of 20 ℃ and a relative humidity of 90%. How much water needs to be pumped out to reduce it to 70%? Absolute moisture content: 20 ℃ -90%=15.60135 g/m3 Absolute moisture content: 20 ℃ -70%=12.13438 g/m3 Then, by substituting the above formula, the required humidification amount can be calculated: Example 1 Desiccation amount required (kg/h)=40000m3 × one point two × (15.60135-12.13438) kg/m3 ÷ 1000 × 1.2=201.6 kg Example 2: Required dehumidification capacity (kg/h)=100000m3 × one point two × (15.60135-12.13438) kg/m3 ÷ 1000 × 1.2=504 kg Conclusion: The water to be removed in Example 1 is 201.6 kg, and the water to be removed in Example 2 is 504 kg. In addition, it should be noted that the relative humidity of the environment is related to the temperature of the environment. The higher the temperature is, the faster the humidity will evaporate, otherwise the worse the effect will be. Therefore, when configuring an industrial dehumidifier, it is necessary to select the model under the guidance of professionals and contact PARKOO
ρ Represents the Density of air 1.2
V1 represents the volume of dehumidification space
V2 represents the volume of fresh air 1.1
X1 represents the air moisture content before dehumidification (the air moisture content at the humidity of 95% RH and the temperature of 18 ℃ is 0.013kg/kg dry air from the table)
X2 represents the air moisture content after dehumidification (the air moisture content at the humidity of 70% RH and the temperature of 18 ℃ is 0.009kg/kg dry air from the table)
C represents an insurance coefficient of 1.2
Example analysis:
(1) Place of use: finished product warehouse
(2) Overall space: 1200 ㎡ * 4.8m=5760m ³; Sealing situation: The door is open but not closed
(4) Environmental conditions before dehumidification: Indoor temperature: 23 ℃ Humidity: about RH72%
(5) Dehumidification requirements: Control the relative humidity of indoor air at RH60%
(6) With or without air conditioner/Whole-house fan: without
Warehouse volume: 5760m ³ ;
Required humidity: 60% Substitute it into the calculation formula to obtain the dehumidification capacity: E=1.2 × 5760 * 1.1 × (0.01703-0.01065) × 1.2=58.2kg/h
